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1131341220103 = 5993720464541
BaseRepresentation
bin10000011101101001001…
…100010000100100000111
311000011012010002201012111
4100131221030100210013
5122013441323020403
62223421520401451
7144510455463043
oct20355114204407
94004163081174
101131341220103
113a6887696596
12163317a76287
13828b9cab323
143ca85ac3023
151e66720d56d
hex10769310907

1131341220103 has 8 divisors (see below), whose sum is σ = 1151744423760. Its totient is φ = 1110978947520.

The previous prime is 1131341220091. The next prime is 1131341220127. The reversal of 1131341220103 is 3010221431311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1131341220103 - 217 = 1131341089031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131341220133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10176988 + ... + 10287553.

It is an arithmetic number, because the mean of its divisors is an integer number (143968052970).

Almost surely, 21131341220103 is an apocalyptic number.

1131341220103 is a deficient number, since it is larger than the sum of its proper divisors (20403203657).

1131341220103 is an equidigital number, since it uses as much as digits as its factorization.

1131341220103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20465537.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1131341220103 its reverse (3010221431311), we get a palindrome (4141562651414).

The spelling of 1131341220103 in words is "one trillion, one hundred thirty-one billion, three hundred forty-one million, two hundred twenty thousand, one hundred three".

Divisors: 1 59 937 55283 20464541 1207407919 19175274917 1131341220103