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1131342031203 = 3377114010401
BaseRepresentation
bin10000011101101001001…
…111010110100101100011
311000011012011121220211020
4100131221033112211203
5122013442024444303
62223421550020523
7144510465411546
oct20355117264543
94004164556736
101131342031203
113a688809aa1a
121633181a7743
13828ba203577
143ca85c5485d
151e66731da53
hex107693d6963

1131342031203 has 4 divisors (see below), whose sum is σ = 1508456041608. Its totient is φ = 754228020800.

The previous prime is 1131342031121. The next prime is 1131342031207. The reversal of 1131342031203 is 3021302431311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131342031203 - 29 = 1131342030691 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1131342031207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188557005198 + ... + 188557005203.

It is an arithmetic number, because the mean of its divisors is an integer number (377114010402).

Almost surely, 21131342031203 is an apocalyptic number.

1131342031203 is a deficient number, since it is larger than the sum of its proper divisors (377114010405).

1131342031203 is an equidigital number, since it uses as much as digits as its factorization.

1131342031203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377114010404.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 1131342031203 its reverse (3021302431311), we get a palindrome (4152644462514).

The spelling of 1131342031203 in words is "one trillion, one hundred thirty-one billion, three hundred forty-two million, thirty-one thousand, two hundred three".

Divisors: 1 3 377114010401 1131342031203