11313434354051 has 4 divisors (see below), whose sum is σ = 11322157126632. Its totient is φ = 11304711581472.

The previous prime is 11313434353999. The next prime is 11313434354077. The reversal of 11313434354051 is 15045343431311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11313434354051 is a prime.

It is a super-2 number, since 2×11313434354051² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11313434353996 and 11313434354014.

It is not an unprimeable number, because it can be changed into a prime (11313434354851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4361384345 + ... + 4361386938.

It is an arithmetic number, because the mean of its divisors is an integer number (2830539281658).

Almost surely, 2^{11313434354051} is an apocalyptic number.

11313434354051 is a deficient number, since it is larger than the sum of its proper divisors (8722772581).

11313434354051 is an equidigital number, since it uses as much as digits as its factorization.

11313434354051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8722772580.

The product of its (nonzero) digits is 129600, while the sum is 38.

Adding to 11313434354051 its reverse (15045343431311), we get a palindrome (26358777785362).

The spelling of 11313434354051 in words is "eleven trillion, three hundred thirteen billion, four hundred thirty-four million, three hundred fifty-four thousand, fifty-one".