1131344208403 has 4 divisors (see below), whose sum is σ = 1131351513408. Its totient is φ = 1131336903400.

The previous prime is 1131344208391. The next prime is 1131344208427. The reversal of 1131344208403 is 3048024431311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131344208403 - 2¹³ = 1131344200211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131344208433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3415048 + ... + 3731653.

It is an arithmetic number, because the mean of its divisors is an integer number (282837878352).

Almost surely, 2^{1131344208403} is an apocalyptic number.

1131344208403 is a deficient number, since it is larger than the sum of its proper divisors (7305005).

1131344208403 is an equidigital number, since it uses as much as digits as its factorization.

1131344208403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7305004.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 1131344208403 its reverse (3048024431311), we get a palindrome (4179368639714).

The spelling of 1131344208403 in words is "one trillion, one hundred thirty-one billion, three hundred forty-four million, two hundred eight thousand, four hundred three".