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1131345035641 = 2867893944869
BaseRepresentation
bin10000011101101001011…
…010110100000101111001
311000011012101021120010201
4100131221122310011321
5122013443312120031
62223422134242201
7144510533064052
oct20355132640571
94004171246121
101131345035641
113a6889862227
121633191b6361
13828baa15c42
143ca863d7729
151e667713d61
hex107696b4179

1131345035641 has 4 divisors (see below), whose sum is σ = 1131349267300. Its totient is φ = 1131340803984.

The previous prime is 1131345035549. The next prime is 1131345035699. The reversal of 1131345035641 is 1465305431311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 288042596416 + 843302439225 = 536696^2 + 918315^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131345035641 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1131345035641.

It is not an unprimeable number, because it can be changed into a prime (1131345035941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685646 + ... + 2259223.

It is an arithmetic number, because the mean of its divisors is an integer number (282837316825).

Almost surely, 21131345035641 is an apocalyptic number.

It is an amenable number.

1131345035641 is a deficient number, since it is larger than the sum of its proper divisors (4231659).

1131345035641 is an equidigital number, since it uses as much as digits as its factorization.

1131345035641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4231658.

The product of its (nonzero) digits is 64800, while the sum is 37.

The spelling of 1131345035641 in words is "one trillion, one hundred thirty-one billion, three hundred forty-five million, thirty-five thousand, six hundred forty-one".

Divisors: 1 286789 3944869 1131345035641