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1131345035642 = 2565672517821
BaseRepresentation
bin10000011101101001011…
…010110100000101111010
311000011012101021120010202
4100131221122310011322
5122013443312120032
62223422134242202
7144510533064053
oct20355132640572
94004171246122
101131345035642
113a6889862228
121633191b6362
13828baa15c43
143ca863d772a
151e667713d62
hex107696b417a

1131345035642 has 4 divisors (see below), whose sum is σ = 1697017553466. Its totient is φ = 565672517820.

The previous prime is 1131345035549. The next prime is 1131345035699. The reversal of 1131345035642 is 2465305431311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 863061438121 + 268283597521 = 929011^2 + 517961^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1131345035596 and 1131345035605.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282836258909 + ... + 282836258912.

Almost surely, 21131345035642 is an apocalyptic number.

1131345035642 is a deficient number, since it is larger than the sum of its proper divisors (565672517824).

1131345035642 is an equidigital number, since it uses as much as digits as its factorization.

1131345035642 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 565672517823.

The product of its (nonzero) digits is 129600, while the sum is 38.

The spelling of 1131345035642 in words is "one trillion, one hundred thirty-one billion, three hundred forty-five million, thirty-five thousand, six hundred forty-two".

Divisors: 1 2 565672517821 1131345035642