Base | Representation |
---|---|
bin | 10000011101101001011… |
… | …100101000011001000101 |
3 | 11000011012102011202120211 |
4 | 100131221130220121011 |
5 | 122013443422341010 |
6 | 2223422152355421 |
7 | 144510540116632 |
oct | 20355134503105 |
9 | 4004172152524 |
10 | 1131345512005 |
11 | 3a688a058115 |
12 | 1633193a5b71 |
13 | 828bab51a07 |
14 | 3ca864bd189 |
15 | 1e6677aa08a |
hex | 10769728645 |
1131345512005 has 4 divisors (see below), whose sum is σ = 1357614614412. Its totient is φ = 905076409600.
The previous prime is 1131345511963. The next prime is 1131345512021. The reversal of 1131345512005 is 5002155431311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 613681090884 + 517664421121 = 783378^2 + 719489^2 .
It is not a de Polignac number, because 1131345512005 - 217 = 1131345380933 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113134551196 + ... + 113134551205.
It is an arithmetic number, because the mean of its divisors is an integer number (339403653603).
Almost surely, 21131345512005 is an apocalyptic number.
It is an amenable number.
1131345512005 is a deficient number, since it is larger than the sum of its proper divisors (226269102407).
1131345512005 is an equidigital number, since it uses as much as digits as its factorization.
1131345512005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 226269102406.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 1131345512005 in words is "one trillion, one hundred thirty-one billion, three hundred forty-five million, five hundred twelve thousand, five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •