Base | Representation |
---|---|
bin | 1010010010100010000100… |
… | …1001111001100110001010 |
3 | 1111001120010021101220010100 |
4 | 2210220201021321212022 |
5 | 2440330022011213002 |
6 | 40021203350430230 |
7 | 2245242036111021 |
oct | 244504111714612 |
9 | 44046107356110 |
10 | 11313500101002 |
11 | 3672034956980 |
12 | 1328770362376 |
13 | 640b211136b8 |
14 | 2b180d6238b8 |
15 | 14945415311c |
hex | a4a2127998a |
11313500101002 has 192 divisors, whose sum is σ = 28160151552000. Its totient is φ = 3251078812800.
The previous prime is 11313500100989. The next prime is 11313500101061. The reversal of 11313500101002 is 20010100531311.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 86575749 + ... + 86706327.
It is an arithmetic number, because the mean of its divisors is an integer number (146667456000).
Almost surely, 211313500101002 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11313500101002, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14080075776000).
11313500101002 is an abundant number, since it is smaller than the sum of its proper divisors (16846651450998).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313500101002 is a wasteful number, since it uses less digits than its factorization.
11313500101002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130897 (or 130894 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 18.
Adding to 11313500101002 its reverse (20010100531311), we get a palindrome (31323600632313).
The spelling of 11313500101002 in words is "eleven trillion, three hundred thirteen billion, five hundred million, one hundred one thousand, two".
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