Base | Representation |
---|---|
bin | 1010010010100010010001… |
… | …1011011111101100011111 |
3 | 1111001120021002210100022211 |
4 | 2210220210123133230133 |
5 | 2440330130042421101 |
6 | 40021213032221251 |
7 | 2245243304120032 |
oct | 244504433375437 |
9 | 44046232710284 |
10 | 11313555045151 |
11 | 3672062974267 |
12 | 132878683a827 |
13 | 640b2c610328 |
14 | 2b1816a47019 |
15 | 149458da7c51 |
hex | a4a246dfb1f |
11313555045151 has 8 divisors (see below), whose sum is σ = 11325238951808. Its totient is φ = 11301871680000.
The previous prime is 11313555045139. The next prime is 11313555045173. The reversal of 11313555045151 is 15154055531311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11313555045151 - 241 = 9114531789599 is a prime.
It is a super-4 number, since 4×113135550451514 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313555045181) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51979351 + ... + 52196551.
It is an arithmetic number, because the mean of its divisors is an integer number (1415654868976).
Almost surely, 211313555045151 is an apocalyptic number.
11313555045151 is a deficient number, since it is larger than the sum of its proper divisors (11683906657).
11313555045151 is an equidigital number, since it uses as much as digits as its factorization.
11313555045151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 270753.
The product of its (nonzero) digits is 112500, while the sum is 40.
The spelling of 11313555045151 in words is "eleven trillion, three hundred thirteen billion, five hundred fifty-five million, forty-five thousand, one hundred fifty-one".
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