1131400212431 has 4 divisors (see below), whose sum is σ = 1146898845552. Its totient is φ = 1115901579312.

The previous prime is 1131400212413. The next prime is 1131400212461. The reversal of 1131400212431 is 1342120041311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131400212431 - 2¹⁸ = 1131399950287 is a prime.

It is a super-2 number, since 2×1131400212431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131400212397 and 1131400212406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131400212461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7749316451 + ... + 7749316596.

It is an arithmetic number, because the mean of its divisors is an integer number (286724711388).

Almost surely, 2^{1131400212431} is an apocalyptic number.

1131400212431 is a deficient number, since it is larger than the sum of its proper divisors (15498633121).

1131400212431 is an equidigital number, since it uses as much as digits as its factorization.

1131400212431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15498633120.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1131400212431 its reverse (1342120041311), we get a palindrome (2473520253742).

The spelling of 1131400212431 in words is "one trillion, one hundred thirty-one billion, four hundred million, two hundred twelve thousand, four hundred thirty-one".