11314011041311 has 4 divisors (see below), whose sum is σ = 12342557499624. Its totient is φ = 10285464583000.

The previous prime is 11314011041303. The next prime is 11314011041321.

11314011041311 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11314011041311 - 2³ = 11314011041303 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11314011041321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 514273229140 + ... + 514273229161.

It is an arithmetic number, because the mean of its divisors is an integer number (3085639374906).

Almost surely, 2^{11314011041311} is an apocalyptic number.

11314011041311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11314011041311 is a deficient number, since it is larger than the sum of its proper divisors (1028546458313).

11314011041311 is a wasteful number, since it uses less digits than its factorization.

11314011041311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1028546458312.

The product of its (nonzero) digits is 144, while the sum is 22.

It can be divided in two parts, 1131401 and 1041311, that added together give a palindrome (2172712).

The spelling of 11314011041311 in words is "eleven trillion, three hundred fourteen billion, eleven million, forty-one thousand, three hundred eleven".