113140113100 has 216 divisors, whose sum is σ = 289624983648. Its totient is φ = 38247552000.

The previous prime is 113140113043. The next prime is 113140113157. The reversal of 113140113100 is 1311041311.

It is an interprime number because it is at equal distance from previous prime (113140113043) and next prime (113140113157).

It is a super-2 number, since 2×113140113100² (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 188252800 + ... + 188253400.

Almost surely, 2^113140113100 is an apocalyptic number.

113140113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113140113100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (144812491824).

113140113100 is an abundant number, since it is smaller than the sum of its proper divisors (176484870548).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113140113100 is a wasteful number, since it uses less digits than its factorization.

113140113100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1105 (or 1091 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 113140113100 its reverse (1311041311), we get a palindrome (114451154411).

The spelling of 113140113100 in words is "one hundred thirteen billion, one hundred forty million, one hundred thirteen thousand, one hundred".