Base | Representation |
---|---|
bin | 110100101011110101… |
… | …1111111100100001001 |
3 | 101211000221102202012000 |
4 | 1221113223333210021 |
5 | 3323202404100131 |
6 | 123550445141213 |
7 | 11113502453106 |
oct | 1512753774411 |
9 | 354027382160 |
10 | 113140300041 |
11 | 43a89827aaa |
12 | 19b1655a809 |
13 | a890c95202 |
14 | 56942abaad |
15 | 2e22b51ce6 |
hex | 1a57aff909 |
113140300041 has 16 divisors (see below), whose sum is σ = 167693560320. Its totient is φ = 75391631280.
The previous prime is 113140299983. The next prime is 113140300057. The reversal of 113140300041 is 140003041311.
113140300041 is a `hidden beast` number, since 11 + 314 + 0 + 300 + 0 + 41 = 666.
It is not a de Polignac number, because 113140300041 - 219 = 113139775753 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 113140299987 and 113140300023.
It is not an unprimeable number, because it can be changed into a prime (113140300081) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 919830 + ... + 1035551.
It is an arithmetic number, because the mean of its divisors is an integer number (10480847520).
Almost surely, 2113140300041 is an apocalyptic number.
It is an amenable number.
113140300041 is a deficient number, since it is larger than the sum of its proper divisors (54553260279).
113140300041 is a wasteful number, since it uses less digits than its factorization.
113140300041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1957533 (or 1957527 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 113140300041 its reverse (140003041311), we get a palindrome (253143341352).
The spelling of 113140300041 in words is "one hundred thirteen billion, one hundred forty million, three hundred thousand, forty-one".
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