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113140300057 is a prime number
BaseRepresentation
bin110100101011110101…
…1111111100100011001
3101211000221102202012121
41221113223333210121
53323202404100212
6123550445141241
711113502453131
oct1512753774431
9354027382177
10113140300057
1143a89828014
1219b1655a821
13a890c95215
1456942abac1
152e22b51d07
hex1a57aff919

113140300057 has 2 divisors, whose sum is σ = 113140300058. Its totient is φ = 113140300056.

The previous prime is 113140299983. The next prime is 113140300081. The reversal of 113140300057 is 750003041311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105825945481 + 7314354576 = 325309^2 + 85524^2 .

It is a cyclic number.

It is not a de Polignac number, because 113140300057 - 223 = 113131911449 is a prime.

It is not a weakly prime, because it can be changed into another prime (113140300087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56570150028 + 56570150029.

It is an arithmetic number, because the mean of its divisors is an integer number (56570150029).

Almost surely, 2113140300057 is an apocalyptic number.

It is an amenable number.

113140300057 is a deficient number, since it is larger than the sum of its proper divisors (1).

113140300057 is an equidigital number, since it uses as much as digits as its factorization.

113140300057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 25.

Adding to 113140300057 its reverse (750003041311), we get a palindrome (863143341368).

The spelling of 113140300057 in words is "one hundred thirteen billion, one hundred forty million, three hundred thousand, fifty-seven".