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11314031223 = 3112314906497
BaseRepresentation
bin10101000100101111…
…00110101001110111
31002012111100100002110
422202113212221313
5141132342444343
65110402542103
7550241451525
oct124227465167
932174310073
1011314031223
114886526130
122239067933
1310b3cc8b41
14794897315
15463420833
hex2a25e6a77

11314031223 has 16 divisors (see below), whose sum is σ = 17172285696. Its totient is φ = 6558858240.

The previous prime is 11314031191. The next prime is 11314031227. The reversal of 11314031223 is 32213041311.

It is not a de Polignac number, because 11314031223 - 25 = 11314031191 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11314031223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11314031227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7452490 + ... + 7454007.

It is an arithmetic number, because the mean of its divisors is an integer number (1073267856).

Almost surely, 211314031223 is an apocalyptic number.

11314031223 is a deficient number, since it is larger than the sum of its proper divisors (5858254473).

11314031223 is a wasteful number, since it uses less digits than its factorization.

11314031223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14906534.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11314031223 its reverse (32213041311), we get a palindrome (43527072534).

The spelling of 11314031223 in words is "eleven billion, three hundred fourteen million, thirty-one thousand, two hundred twenty-three".

Divisors: 1 3 11 23 33 69 253 759 14906497 44719491 163971467 342849431 491914401 1028548293 3771343741 11314031223