Base | Representation |
---|---|
bin | 11001101110011010001110… |
… | …000110010110100001010111 |
3 | 112211121010011212210012012020 |
4 | 121232122032012112201113 |
5 | 104312143031102303030 |
6 | 1040343553223224223 |
7 | 32555060615626506 |
oct | 3156321606264127 |
9 | 484533155705166 |
10 | 113140412541015 |
11 | 330606413511a2 |
12 | 108334532a8073 |
13 | 4b19130ca5c52 |
14 | 1dd204d17283d |
15 | d13095eb7510 |
hex | 66e68e196857 |
113140412541015 has 16 divisors (see below), whose sum is σ = 185917218446688. Its totient is φ = 58710700561536.
The previous prime is 113140412540993. The next prime is 113140412541017. The reversal of 113140412541015 is 510145214041311.
It is not a de Polignac number, because 113140412541015 - 212 = 113140412536919 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113140412541017) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 101928299032 + ... + 101928300141.
It is an arithmetic number, because the mean of its divisors is an integer number (11619826152918).
Almost surely, 2113140412541015 is an apocalyptic number.
113140412541015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
113140412541015 is a deficient number, since it is larger than the sum of its proper divisors (72776805905673).
113140412541015 is a wasteful number, since it uses less digits than its factorization.
113140412541015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 203856599218.
The product of its (nonzero) digits is 9600, while the sum is 33.
Adding to 113140412541015 its reverse (510145214041311), we get a palindrome (623285626582326).
The spelling of 113140412541015 in words is "one hundred thirteen trillion, one hundred forty billion, four hundred twelve million, five hundred forty-one thousand, fifteen".
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