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1131404254403 = 19297727265739
BaseRepresentation
bin10000011101101100111…
…100101101110011000011
311000011100111201012000012
4100131230330231303003
5122014103442120103
62223432051415135
7144512152325363
oct20355474556303
94004314635005
101131404254403
113a690a22a155
12163334bb44ab
13828ca07b427
143ca902109a3
151e66ca102d8
hex1076cf2dcc3

1131404254403 has 16 divisors (see below), whose sum is σ = 1232183232000. Its totient is φ = 1034758261152.

The previous prime is 1131404254391. The next prime is 1131404254447. The reversal of 1131404254403 is 3044524041311.

It is a cyclic number.

It is not a de Polignac number, because 1131404254403 - 26 = 1131404254339 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1131404254403.

It is not an unprimeable number, because it can be changed into a prime (1131404854403) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4124708 + ... + 4390446.

It is an arithmetic number, because the mean of its divisors is an integer number (77011452000).

Almost surely, 21131404254403 is an apocalyptic number.

1131404254403 is a deficient number, since it is larger than the sum of its proper divisors (100778977597).

1131404254403 is a wasteful number, since it uses less digits than its factorization.

1131404254403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 273514.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 1131404254403 its reverse (3044524041311), we get a palindrome (4175928295714).

The spelling of 1131404254403 in words is "one trillion, one hundred thirty-one billion, four hundred four million, two hundred fifty-four thousand, four hundred three".

Divisors: 1 19 29 551 7727 146813 224083 265739 4257577 5049041 7706431 146422189 2053365253 39013939807 59547592337 1131404254403