Base | Representation |
---|---|
bin | 10101000100101111… |
… | …01001110111110001 |
3 | 1002012111101000011112 |
4 | 22202113221313301 |
5 | 141132343410101 |
6 | 5110403123105 |
7 | 550241535122 |
oct | 124227516761 |
9 | 32174330145 |
10 | 11314044401 |
11 | 4886535020 |
12 | 2239073495 |
13 | 10b4001b3a |
14 | 79489c049 |
15 | 4634246bb |
hex | 2a25e9df1 |
11314044401 has 8 divisors (see below), whose sum is σ = 12469838304. Its totient is φ = 10179457920.
The previous prime is 11314044397. The next prime is 11314044419. The reversal of 11314044401 is 10444041311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11314044401 - 22 = 11314044397 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11314044481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5300735 + ... + 5302868.
It is an arithmetic number, because the mean of its divisors is an integer number (1558729788).
Almost surely, 211314044401 is an apocalyptic number.
11314044401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
11314044401 is a deficient number, since it is larger than the sum of its proper divisors (1155793903).
11314044401 is a wasteful number, since it uses less digits than its factorization.
11314044401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10603711.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 11314044401 its reverse (10444041311), we get a palindrome (21758085712).
The spelling of 11314044401 in words is "eleven billion, three hundred fourteen million, forty-four thousand, four hundred one".
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