113141014031111 has 4 divisors (see below), whose sum is σ = 123426560761224. Its totient is φ = 102855467301000.

The previous prime is 113141014031099. The next prime is 113141014031117. The reversal of 113141014031111 is 111130410141311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113141014031111 - 2¹⁴ = 113141014014727 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113141014031117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5142773365040 + ... + 5142773365061.

It is an arithmetic number, because the mean of its divisors is an integer number (30856640190306).

Almost surely, 2^{113141014031111} is an apocalyptic number.

113141014031111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

113141014031111 is a deficient number, since it is larger than the sum of its proper divisors (10285546730113).

113141014031111 is a wasteful number, since it uses less digits than its factorization.

113141014031111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10285546730112.

The product of its (nonzero) digits is 144, while the sum is 23.

Adding to 113141014031111 its reverse (111130410141311), we get a palindrome (224271424172422).

The spelling of 113141014031111 in words is "one hundred thirteen trillion, one hundred forty-one billion, fourteen million, thirty-one thousand, one hundred eleven".