Base | Representation |
---|---|
bin | 1010010010100100010100… |
… | …0101111001100100111011 |
3 | 1111001121200021220222010121 |
4 | 2210221011011321210323 |
5 | 2440332240334011443 |
6 | 40021343245354111 |
7 | 2245263006665503 |
oct | 244510505714473 |
9 | 44047607828117 |
10 | 11314103032123 |
11 | 3672314226a61 |
12 | 13288ba268937 |
13 | 640bb8cc7488 |
14 | 2b1869730a03 |
15 | 14948c04e4ed |
hex | a4a4517993b |
11314103032123 has 4 divisors (see below), whose sum is σ = 11315147646688. Its totient is φ = 11313058417560.
The previous prime is 11314103032087. The next prime is 11314103032147. The reversal of 11314103032123 is 32123030141311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11314103032123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11314103032423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 522291036 + ... + 522312697.
It is an arithmetic number, because the mean of its divisors is an integer number (2828786911672).
Almost surely, 211314103032123 is an apocalyptic number.
11314103032123 is a deficient number, since it is larger than the sum of its proper divisors (1044614565).
11314103032123 is a wasteful number, since it uses less digits than its factorization.
11314103032123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1044614564.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11314103032123 its reverse (32123030141311), we get a palindrome (43437133173434).
The spelling of 11314103032123 in words is "eleven trillion, three hundred fourteen billion, one hundred three million, thirty-two thousand, one hundred twenty-three".
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