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113141042017 = 1667186736353
BaseRepresentation
bin110100101011110111…
…0110100101101100001
3101211000222211102222121
41221113232310231201
53323203101321032
6123550513104241
711113511663233
oct1512756645541
9354028742877
10113141042017
1143a8a194503
1219b16858081
13a891194b53
145694422253
152e22c4ba97
hex1a57bb4b61

113141042017 has 8 divisors (see below), whose sum is σ = 113272665696. Its totient is φ = 113009498112.

The previous prime is 113141041991. The next prime is 113141042137. The reversal of 113141042017 is 710240141311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113141042017 - 211 = 113141039969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113141041982 and 113141042000.

It is not an unprimeable number, because it can be changed into a prime (113141042317) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3094113 + ... + 3130465.

It is an arithmetic number, because the mean of its divisors is an integer number (14159083212).

Almost surely, 2113141042017 is an apocalyptic number.

It is an amenable number.

113141042017 is a deficient number, since it is larger than the sum of its proper divisors (131623679).

113141042017 is a wasteful number, since it uses less digits than its factorization.

113141042017 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39887.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 113141042017 its reverse (710240141311), we get a palindrome (823381183328).

The spelling of 113141042017 in words is "one hundred thirteen billion, one hundred forty-one million, forty-two thousand, seventeen".

Divisors: 1 1667 1867 36353 3112289 60600451 67871051 113141042017