1131420300132 has 48 divisors (see below), whose sum is σ = 2731162815360. Its totient is φ = 364115496192.

The previous prime is 1131420300091. The next prime is 1131420300181. The reversal of 1131420300132 is 2310030241311.

It is a super-2 number, since 2×1131420300132² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131420300099 and 1131420300108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7190848 + ... + 7346504.

It is an arithmetic number, because the mean of its divisors is an integer number (56899225320).

Almost surely, 2^{1131420300132} is an apocalyptic number.

1131420300132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1131420300132 is an abundant number, since it is smaller than the sum of its proper divisors (1599742515228).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131420300132 is a wasteful number, since it uses less digits than its factorization.

1131420300132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 176580 (or 176578 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1131420300132 its reverse (2310030241311), we get a palindrome (3441450541443).

The spelling of 1131420300132 in words is "one trillion, one hundred thirty-one billion, four hundred twenty million, three hundred thousand, one hundred thirty-two".