11314231133 has 4 divisors (see below), whose sum is σ = 11389159968. Its totient is φ = 11239302300.

The previous prime is 11314231121. The next prime is 11314231163. The reversal of 11314231133 is 33113241311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33113241311 = 757 ⋅43742723.

It is a cyclic number.

It is not a de Polignac number, because 11314231133 - 2⁶ = 11314231069 is a prime.

It is a super-2 number, since 2×11314231133² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11314231099 and 11314231108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11314231163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37464191 + ... + 37464492.

It is an arithmetic number, because the mean of its divisors is an integer number (2847289992).

Almost surely, 2^11314231133 is an apocalyptic number.

It is an amenable number.

11314231133 is a deficient number, since it is larger than the sum of its proper divisors (74928835).

11314231133 is an equidigital number, since it uses as much as digits as its factorization.

11314231133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74928834.

The product of its digits is 648, while the sum is 23.

Adding to 11314231133 its reverse (33113241311), we get a palindrome (44427472444).

The spelling of 11314231133 in words is "eleven billion, three hundred fourteen million, two hundred thirty-one thousand, one hundred thirty-three".