Base | Representation |
---|---|
bin | 110100101011111001… |
… | …1101011010100111111 |
3 | 101211001002020002020022 |
4 | 1221113303223110333 |
5 | 3323203413024203 |
6 | 123551000242355 |
7 | 11113525542434 |
oct | 1512763532477 |
9 | 354032202208 |
10 | 113142314303 |
11 | 43a8a983387 |
12 | 19b171703bb |
13 | a89151bc95 |
14 | 5694673b8b |
15 | 2e22deda38 |
hex | 1a57ceb53f |
113142314303 has 4 divisors (see below), whose sum is σ = 113143145808. Its totient is φ = 113141482800.
The previous prime is 113142314251. The next prime is 113142314309. The reversal of 113142314303 is 303413241311.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 303413241311 = 23 ⋅13191880057.
It is a cyclic number.
It is not a de Polignac number, because 113142314303 - 26 = 113142314239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113142314309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158651 + ... + 501452.
It is an arithmetic number, because the mean of its divisors is an integer number (28285786452).
Almost surely, 2113142314303 is an apocalyptic number.
113142314303 is a deficient number, since it is larger than the sum of its proper divisors (831505).
113142314303 is an equidigital number, since it uses as much as digits as its factorization.
113142314303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 831504.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 113142314303 its reverse (303413241311), we get a palindrome (416555555614).
The spelling of 113142314303 in words is "one hundred thirteen billion, one hundred forty-two million, three hundred fourteen thousand, three hundred three".
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