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113142400403 = 973021138609
BaseRepresentation
bin110100101011111010…
…0000000010110010011
3101211001002101110100012
41221113310000112103
53323203423303103
6123551002145135
711113526351444
oct1512764002623
9354032343305
10113142400403
1143a8aa3203a
1219b171b21ab
13a89154c226
1456946972cb
152e22e192d8
hex1a57d00593

113142400403 has 8 divisors (see below), whose sum is σ = 114315561360. Its totient is φ = 111969377280.

The previous prime is 113142400387. The next prime is 113142400417. The reversal of 113142400403 is 304004241311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113142400403 - 24 = 113142400387 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113142400303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2911163 + ... + 2949771.

It is an arithmetic number, because the mean of its divisors is an integer number (14289445170).

Almost surely, 2113142400403 is an apocalyptic number.

113142400403 is a deficient number, since it is larger than the sum of its proper divisors (1173160957).

113142400403 is an equidigital number, since it uses as much as digits as its factorization.

113142400403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68917.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 113142400403 its reverse (304004241311), we get a palindrome (417146641714).

The spelling of 113142400403 in words is "one hundred thirteen billion, one hundred forty-two million, four hundred thousand, four hundred three".

Divisors: 1 97 30211 38609 2930467 3745073 1166416499 113142400403