1131431343135 has 16 divisors (see below), whose sum is σ = 1835088645984. Its totient is φ = 595163884032.

The previous prime is 1131431343127. The next prime is 1131431343157. The reversal of 1131431343135 is 5313431341311.

It is not a de Polignac number, because 1131431343135 - 2³ = 1131431343127 is a prime.

It is a super-2 number, since 2×1131431343135² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131431343096 and 1131431343105.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 516634222 + ... + 516636411.

It is an arithmetic number, because the mean of its divisors is an integer number (114693040374).

Almost surely, 2^{1131431343135} is an apocalyptic number.

1131431343135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1131431343135 is a deficient number, since it is larger than the sum of its proper divisors (703657302849).

1131431343135 is a wasteful number, since it uses less digits than its factorization.

1131431343135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1033270714.

The product of its digits is 19440, while the sum is 33.

Adding to 1131431343135 its reverse (5313431341311), we get a palindrome (6444862684446).

The spelling of 1131431343135 in words is "one trillion, one hundred thirty-one billion, four hundred thirty-one million, three hundred forty-three thousand, one hundred thirty-five".