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113143241120 = 25571359912973
BaseRepresentation
bin110100101011111011…
…1001101100110100000
3101211001010222011120212
41221113313031212200
53323204132203440
6123551032153252
711113536452510
oct1512767154640
9354033864525
10113143241120
1143a90456748
1219b17538828
13a891784ab0
145694835840
152e23033465
hex1a57dcd9a0

113143241120 has 192 divisors, whose sum is σ = 329560358400. Its totient is φ = 35745435648.

The previous prime is 113143241089. The next prime is 113143241131. The reversal of 113143241120 is 21142341311.

It is a super-2 number, since 2×1131432411202 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8714954 + ... + 8727926.

It is an arithmetic number, because the mean of its divisors is an integer number (1716460200).

Almost surely, 2113143241120 is an apocalyptic number.

113143241120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113143241120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164780179200).

113143241120 is an abundant number, since it is smaller than the sum of its proper divisors (216417117280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113143241120 is a wasteful number, since it uses less digits than its factorization.

113143241120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13607 (or 13599 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 113143241120 its reverse (21142341311), we get a palindrome (134285582431).

The spelling of 113143241120 in words is "one hundred thirteen billion, one hundred forty-three million, two hundred forty-one thousand, one hundred twenty".