11314331101401 has 4 divisors (see below), whose sum is σ = 15085774801872. Its totient is φ = 7542887400932.

The previous prime is 11314331101399. The next prime is 11314331101433. The reversal of 11314331101401 is 10410113341311.

11314331101401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11314331101401 - 2¹ = 11314331101399 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11314331101471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885721850231 + ... + 1885721850236.

It is an arithmetic number, because the mean of its divisors is an integer number (3771443700468).

Almost surely, 2^{11314331101401} is an apocalyptic number.

It is an amenable number.

11314331101401 is a deficient number, since it is larger than the sum of its proper divisors (3771443700471).

11314331101401 is an equidigital number, since it uses as much as digits as its factorization.

11314331101401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3771443700470.

The product of its (nonzero) digits is 432, while the sum is 24.

Adding to 11314331101401 its reverse (10410113341311), we get a palindrome (21724444442712).

The spelling of 11314331101401 in words is "eleven trillion, three hundred fourteen billion, three hundred thirty-one million, one hundred one thousand, four hundred one".