11314343413333 has 8 divisors (see below), whose sum is σ = 11979996925248. Its totient is φ = 10648701445824.

The previous prime is 11314343413223. The next prime is 11314343413349. The reversal of 11314343413333 is 33331434341311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11314343413333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11314343413292 and 11314343413301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11314343413033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 826291 + ... + 4828192.

It is an arithmetic number, because the mean of its divisors is an integer number (1497499615656).

Almost surely, 2^{11314343413333} is an apocalyptic number.

It is an amenable number.

11314343413333 is a deficient number, since it is larger than the sum of its proper divisors (665653511915).

11314343413333 is a wasteful number, since it uses less digits than its factorization.

11314343413333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5772203.

The product of its digits is 139968, while the sum is 37.

Adding to 11314343413333 its reverse (33331434341311), we get a palindrome (44645777754644).

The spelling of 11314343413333 in words is "eleven trillion, three hundred fourteen billion, three hundred forty-three million, four hundred thirteen thousand, three hundred thirty-three".