113144004403 has 4 divisors (see below), whose sum is σ = 113145051688. Its totient is φ = 113142957120.

The previous prime is 113144004371. The next prime is 113144004439. The reversal of 113144004403 is 304400441311.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 304400441311 = 9851 ⋅30900461.

It is a cyclic number.

It is not a de Polignac number, because 113144004403 - 2⁵ = 113144004371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113144004473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 340158 + ... + 584803.

It is an arithmetic number, because the mean of its divisors is an integer number (28286262922).

Almost surely, 2^113144004403 is an apocalyptic number.

113144004403 is a deficient number, since it is larger than the sum of its proper divisors (1047285).

113144004403 is an equidigital number, since it uses as much as digits as its factorization.

113144004403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1047284.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 113144004403 its reverse (304400441311), we get a palindrome (417544445714).

The spelling of 113144004403 in words is "one hundred thirteen billion, one hundred forty-four million, four thousand, four hundred three".