11314402113033 has 24 divisors (see below), whose sum is σ = 16611207866240. Its totient is φ = 7419162094560.

The previous prime is 11314402113031. The next prime is 11314402113097. The reversal of 11314402113033 is 33031120441311.

11314402113033 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 440 + 211 + 3 + 0 + 3 + 3 = 666.

It is not a de Polignac number, because 11314402113033 - 2¹ = 11314402113031 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11314402112988 and 11314402113006.

It is not an unprimeable number, because it can be changed into a prime (11314402113031) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 46466160 + ... + 46709022.

Almost surely, 2^{11314402113033} is an apocalyptic number.

It is an amenable number.

11314402113033 is a deficient number, since it is larger than the sum of its proper divisors (5296805753207).

11314402113033 is a wasteful number, since it uses less digits than its factorization.

11314402113033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 327789 (or 327786 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 11314402113033 its reverse (33031120441311), we get a palindrome (44345522554344).

The spelling of 11314402113033 in words is "eleven trillion, three hundred fourteen billion, four hundred two million, one hundred thirteen thousand, thirty-three".