Base | Representation |
---|---|
bin | 11001101110100011101001… |
… | …111000001010100110100011 |
3 | 112211122002022211122021012021 |
4 | 121232203221320022212203 |
5 | 104312324302304320033 |
6 | 1040352350322242311 |
7 | 32555566630054006 |
oct | 3156435170124643 |
9 | 484562284567167 |
10 | 113150542260643 |
11 | 3306496a306508 |
12 | 108353bb7b6397 |
13 | 4b1a0868113a4 |
14 | 1dd273062153d |
15 | d1348a44ab2d |
hex | 66e8e9e0a9a3 |
113150542260643 has 16 divisors (see below), whose sum is σ = 118731177907200. Its totient is φ = 107625008497600.
The previous prime is 113150542260641. The next prime is 113150542260673. The reversal of 113150542260643 is 346062245051311.
It is a cyclic number.
It is not a de Polignac number, because 113150542260643 - 21 = 113150542260641 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 113150542260643.
It is not an unprimeable number, because it can be changed into a prime (113150542260641) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 628695318 + ... + 628875268.
It is an arithmetic number, because the mean of its divisors is an integer number (7420698619200).
Almost surely, 2113150542260643 is an apocalyptic number.
113150542260643 is a deficient number, since it is larger than the sum of its proper divisors (5580635646557).
113150542260643 is a wasteful number, since it uses less digits than its factorization.
113150542260643 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 332882.
The product of its (nonzero) digits is 518400, while the sum is 43.
The spelling of 113150542260643 in words is "one hundred thirteen trillion, one hundred fifty billion, five hundred forty-two million, two hundred sixty thousand, six hundred forty-three".
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