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113150542260641 is a prime number
BaseRepresentation
bin11001101110100011101001…
…111000001010100110100001
3112211122002022211122021012012
4121232203221320022212201
5104312324302304320031
61040352350322242305
732555566630054004
oct3156435170124641
9484562284567165
10113150542260641
113306496a306506
12108353bb7b6395
134b1a0868113a2
141dd273062153b
15d1348a44ab2b
hex66e8e9e0a9a1

113150542260641 has 2 divisors, whose sum is σ = 113150542260642. Its totient is φ = 113150542260640.

The previous prime is 113150542260629. The next prime is 113150542260673. The reversal of 113150542260641 is 146062245051311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65343053085025 + 47807489175616 = 8083505^2 + 6914296^2 .

It is a cyclic number.

It is not a de Polignac number, because 113150542260641 - 222 = 113150538066337 is a prime.

It is not a weakly prime, because it can be changed into another prime (113150542265641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56575271130320 + 56575271130321.

It is an arithmetic number, because the mean of its divisors is an integer number (56575271130321).

Almost surely, 2113150542260641 is an apocalyptic number.

It is an amenable number.

113150542260641 is a deficient number, since it is larger than the sum of its proper divisors (1).

113150542260641 is an equidigital number, since it uses as much as digits as its factorization.

113150542260641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 41.

The spelling of 113150542260641 in words is "one hundred thirteen trillion, one hundred fifty billion, five hundred forty-two million, two hundred sixty thousand, six hundred forty-one".