Base | Representation |
---|---|
bin | 10000011101110011010… |
… | …001101111100101100011 |
3 | 11000011121220111110121121 |
4 | 100131303101233211203 |
5 | 122014313132230201 |
6 | 2223450403233111 |
7 | 144514611651361 |
oct | 20356321574543 |
9 | 4004556443547 |
10 | 1131510430051 |
11 | 3a6964159521 |
12 | 163364678797 |
13 | 82916074b61 |
14 | 3caa036c631 |
15 | 1e676ed49a1 |
hex | 1077346f963 |
1131510430051 has 8 divisors (see below), whose sum is σ = 1191075972800. Its totient is φ = 1071946123560.
The previous prime is 1131510430031. The next prime is 1131510430081. The reversal of 1131510430051 is 1500340151311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131510430051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1131510429998 and 1131510430025.
It is not an unprimeable number, because it can be changed into a prime (1131510430031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2019616 + ... + 2518306.
It is an arithmetic number, because the mean of its divisors is an integer number (148884496600).
Almost surely, 21131510430051 is an apocalyptic number.
1131510430051 is a deficient number, since it is larger than the sum of its proper divisors (59565542749).
1131510430051 is a wasteful number, since it uses less digits than its factorization.
1131510430051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 618129.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 1131510430051 its reverse (1500340151311), we get a palindrome (2631850581362).
The spelling of 1131510430051 in words is "one trillion, one hundred thirty-one billion, five hundred ten million, four hundred thirty thousand, fifty-one".
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