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113153142153035 = 522630628430607
BaseRepresentation
bin11001101110100110000100…
…110101111101111101001011
3112211122100001000210111002002
4121232212010311331331023
5104312400113342344120
61040353500315101215
732556021226556135
oct3156460465757513
9484570030714062
10113153142153035
1133065a83938106
1210835a0644180b
134b1a3ac34735a
141dd28d9a36055
15d1358d809375
hex66e984d7df4b

113153142153035 has 4 divisors (see below), whose sum is σ = 135783770583648. Its totient is φ = 90522513722424.

The previous prime is 113153142153017. The next prime is 113153142153047. The reversal of 113153142153035 is 530351241351311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113153142153035 - 230 = 113152068411211 is a prime.

It is a super-2 number, since 2×1131531421530352 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113153142153035.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11315314215299 + ... + 11315314215308.

It is an arithmetic number, because the mean of its divisors is an integer number (33945942645912).

Almost surely, 2113153142153035 is an apocalyptic number.

113153142153035 is a deficient number, since it is larger than the sum of its proper divisors (22630628430613).

113153142153035 is an equidigital number, since it uses as much as digits as its factorization.

113153142153035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22630628430612.

The product of its (nonzero) digits is 81000, while the sum is 38.

The spelling of 113153142153035 in words is "one hundred thirteen trillion, one hundred fifty-three billion, one hundred forty-two million, one hundred fifty-three thousand, thirty-five".

Divisors: 1 5 22630628430607 113153142153035