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11315327353 = 111028666123
BaseRepresentation
bin10101000100111001…
…00011000101111001
31002012120210012001021
422202130203011321
5141133210433403
65110450422441
7550255460401
oct124234430571
932176705037
1011315327353
114887230a10
122239591a21
1310b4360a95
14794b13801
154635c98bd
hex2a2723179

11315327353 has 4 divisors (see below), whose sum is σ = 12343993488. Its totient is φ = 10286661220.

The previous prime is 11315327351. The next prime is 11315327357. The reversal of 11315327353 is 35372351311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11315327353 - 21 = 11315327351 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11315327351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 514333051 + ... + 514333072.

It is an arithmetic number, because the mean of its divisors is an integer number (3085998372).

Almost surely, 211315327353 is an apocalyptic number.

It is an amenable number.

11315327353 is a deficient number, since it is larger than the sum of its proper divisors (1028666135).

11315327353 is a wasteful number, since it uses less digits than its factorization.

11315327353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1028666134.

The product of its digits is 28350, while the sum is 34.

Adding to 11315327353 its reverse (35372351311), we get a palindrome (46687678664).

The spelling of 11315327353 in words is "eleven billion, three hundred fifteen million, three hundred twenty-seven thousand, three hundred fifty-three".

Divisors: 1 11 1028666123 11315327353