11317004256135 has 8 divisors (see below), whose sum is σ = 18107206809840. Its totient is φ = 6035735603264.

The previous prime is 11317004256101. The next prime is 11317004256169. The reversal of 11317004256135 is 53165240071311.

It is an interprime number because it is at equal distance from previous prime (11317004256101) and next prime (11317004256169).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11317004256135 - 2¹⁵ = 11317004223367 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11317004256093 and 11317004256102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 377233475190 + ... + 377233475219.

It is an arithmetic number, because the mean of its divisors is an integer number (2263400851230).

Almost surely, 2^{11317004256135} is an apocalyptic number.

11317004256135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11317004256135 is a deficient number, since it is larger than the sum of its proper divisors (6790202553705).

11317004256135 is an equidigital number, since it uses as much as digits as its factorization.

11317004256135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 754466950417.

The product of its (nonzero) digits is 75600, while the sum is 39.

It can be divided in two parts, 1131700 and 4256135, that added together give a palindrome (5387835).

The spelling of 11317004256135 in words is "eleven trillion, three hundred seventeen billion, four million, two hundred fifty-six thousand, one hundred thirty-five".