Base | Representation |
---|---|
bin | 10000011110010001001… |
… | …000000010101011111011 |
3 | 11000012220210210101101211 |
4 | 100132101020002223323 |
5 | 122021324332001243 |
6 | 2224012212423551 |
7 | 144533202315640 |
oct | 20362110025373 |
9 | 4005823711354 |
10 | 1132011203323 |
11 | 3a70a08a3930 |
12 | 163484317bb7 |
13 | 82995a3abc0 |
14 | 3cb0aa85dc7 |
15 | 1e6a5e51d9d |
hex | 10791202afb |
1132011203323 has 64 divisors (see below), whose sum is σ = 1601854894080. Its totient is φ = 770435971200.
The previous prime is 1132011203303. The next prime is 1132011203333. The reversal of 1132011203323 is 3233021102311.
It is not a de Polignac number, because 1132011203323 - 221 = 1132009106171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1132011203294 and 1132011203303.
It is not an unprimeable number, because it can be changed into a prime (1132011203303) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 15692728 + ... + 15764698.
It is an arithmetic number, because the mean of its divisors is an integer number (25028982720).
Almost surely, 21132011203323 is an apocalyptic number.
1132011203323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1132011203323 is a deficient number, since it is larger than the sum of its proper divisors (469843690757).
1132011203323 is a wasteful number, since it uses less digits than its factorization.
1132011203323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72848.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1132011203323 its reverse (3233021102311), we get a palindrome (4365032305634).
The spelling of 1132011203323 in words is "one trillion, one hundred thirty-two billion, eleven million, two hundred three thousand, three hundred twenty-three".
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