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11320131421 = 23492179627
BaseRepresentation
bin10101000101011101…
…10111111101011101
31002012220211020222201
422202232313331131
5141140423201141
65111141411501
7550344346414
oct124256677535
932186736881
1011320131421
114889a12315
12223b109b91
1310b5353621
1479560447b
15463c28031
hex2a2bb7f5d

11320131421 has 4 divisors (see below), whose sum is σ = 11812311072. Its totient is φ = 10827951772.

The previous prime is 11320131419. The next prime is 11320131481. The reversal of 11320131421 is 12413102311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11320131421 - 21 = 11320131419 is a prime.

It is a super-2 number, since 2×113201314212 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11320131481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 246089791 + ... + 246089836.

It is an arithmetic number, because the mean of its divisors is an integer number (2953077768).

Almost surely, 211320131421 is an apocalyptic number.

It is an amenable number.

11320131421 is a deficient number, since it is larger than the sum of its proper divisors (492179651).

11320131421 is an equidigital number, since it uses as much as digits as its factorization.

11320131421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 492179650.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11320131421 its reverse (12413102311), we get a palindrome (23733233732).

The spelling of 11320131421 in words is "eleven billion, three hundred twenty million, one hundred thirty-one thousand, four hundred twenty-one".

Divisors: 1 23 492179627 11320131421