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11320141163341 = 19875697101743
BaseRepresentation
bin1010010010111010110011…
…1111100010101101001101
31111002012021002201211000011
42210232230333202231031
52440432122114211331
640024222343433221
72245565436156553
oct244565477425515
944065232654004
1011320141163341
11367493263134a
121329b04455811
1364163bc5429a
142b1c7d627bd3
151496e21ba3b1
hexa4bacfe2b4d

11320141163341 has 4 divisors (see below), whose sum is σ = 11325838267072. Its totient is φ = 11314444059612.

The previous prime is 11320141163311. The next prime is 11320141163351. The reversal of 11320141163341 is 14336114102311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11320141163341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11320141163311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2848548885 + ... + 2848552858.

It is an arithmetic number, because the mean of its divisors is an integer number (2831459566768).

Almost surely, 211320141163341 is an apocalyptic number.

It is an amenable number.

11320141163341 is a deficient number, since it is larger than the sum of its proper divisors (5697103731).

11320141163341 is an equidigital number, since it uses as much as digits as its factorization.

11320141163341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5697103730.

The product of its (nonzero) digits is 5184, while the sum is 31.

Adding to 11320141163341 its reverse (14336114102311), we get a palindrome (25656255265652).

The spelling of 11320141163341 in words is "eleven trillion, three hundred twenty billion, one hundred forty-one million, one hundred sixty-three thousand, three hundred forty-one".

Divisors: 1 1987 5697101743 11320141163341