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1132014310441 = 7331488568973
BaseRepresentation
bin10000011110010001010…
…011111001010000101001
311000012221000122020120021
4100132101103321100221
5122021331130413231
62224012403200441
7144533240606410
oct20362123712051
94005830566507
101132014310441
113a70a26262a3
12163485376121
1382996588231
143cb0b254477
151e6a6367811
hex107914f9429

1132014310441 has 8 divisors (see below), whose sum is σ = 1297639194944. Its totient is φ = 967366564560.

The previous prime is 1132014310439. The next prime is 1132014310457. The reversal of 1132014310441 is 1440134102311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1132014310441 - 21 = 1132014310439 is a prime.

It is a super-2 number, since 2×11320143104412 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1132014310421) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 244282170 + ... + 244286803.

It is an arithmetic number, because the mean of its divisors is an integer number (162204899368).

Almost surely, 21132014310441 is an apocalyptic number.

It is an amenable number.

1132014310441 is a deficient number, since it is larger than the sum of its proper divisors (165624884503).

1132014310441 is an equidigital number, since it uses as much as digits as its factorization.

1132014310441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 488569311.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1132014310441 its reverse (1440134102311), we get a palindrome (2572148412752).

The spelling of 1132014310441 in words is "one trillion, one hundred thirty-two billion, fourteen million, three hundred ten thousand, four hundred forty-one".

Divisors: 1 7 331 2317 488568973 3419982811 161716330063 1132014310441