Base | Representation |
---|---|
bin | 10101000101011110… |
… | …01001100010010101 |
3 | 1002012220221220202002 |
4 | 22202233021202111 |
5 | 141140433002123 |
6 | 5111143125045 |
7 | 550345066331 |
oct | 124257114225 |
9 | 32186856662 |
10 | 11320203413 |
11 | 4889a61412 |
12 | 223b143785 |
13 | 10b537a31c |
14 | 7956227c1 |
15 | 463c3e528 |
hex | 2a2bc9895 |
11320203413 has 4 divisors (see below), whose sum is σ = 11339039628. Its totient is φ = 11301367200.
The previous prime is 11320203409. The next prime is 11320203421. The reversal of 11320203413 is 31430202311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6499261924 + 4820941489 = 80618^2 + 69433^2 .
It is a cyclic number.
It is not a de Polignac number, because 11320203413 - 22 = 11320203409 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11320203473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9417206 + ... + 9418407.
It is an arithmetic number, because the mean of its divisors is an integer number (2834759907).
Almost surely, 211320203413 is an apocalyptic number.
It is an amenable number.
11320203413 is a deficient number, since it is larger than the sum of its proper divisors (18836215).
11320203413 is an equidigital number, since it uses as much as digits as its factorization.
11320203413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18836214.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 11320203413 its reverse (31430202311), we get a palindrome (42750405724).
The spelling of 11320203413 in words is "eleven billion, three hundred twenty million, two hundred three thousand, four hundred thirteen".
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