Base | Representation |
---|---|
bin | 1010010010111011000111… |
… | …1011110000000001101001 |
3 | 1111002012110212201011112110 |
4 | 2210232301323300001221 |
5 | 2440432304324233101 |
6 | 40024234504232533 |
7 | 2245600463556432 |
oct | 244566173600151 |
9 | 44065425634473 |
10 | 11320224055401 |
11 | 36749753a8388 |
12 | 1329b2816b749 |
13 | 641653187b41 |
14 | 2b1c8a644489 |
15 | 1496e95e0cd6 |
hex | a4bb1ef0069 |
11320224055401 has 16 divisors (see below), whose sum is σ = 15099801615360. Its totient is φ = 7543731690000.
The previous prime is 11320224055331. The next prime is 11320224055403. The reversal of 11320224055401 is 10455042202311.
It is not a de Polignac number, because 11320224055401 - 215 = 11320224022633 is a prime.
It is a super-3 number, since 3×113202240554013 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11320224055403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 126973426 + ... + 127062548.
It is an arithmetic number, because the mean of its divisors is an integer number (943737600960).
Almost surely, 211320224055401 is an apocalyptic number.
It is an amenable number.
11320224055401 is a deficient number, since it is larger than the sum of its proper divisors (3779577559959).
11320224055401 is a wasteful number, since it uses less digits than its factorization.
11320224055401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105956.
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 11320224055401 its reverse (10455042202311), we get a palindrome (21775266257712).
The spelling of 11320224055401 in words is "eleven trillion, three hundred twenty billion, two hundred twenty-four million, fifty-five thousand, four hundred one".
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