Search a number
-
+
113205434143 = 338935579391
BaseRepresentation
bin110100101101110010…
…0011101011100011111
3101211012110222220101011
41221123210131130133
53323321042343033
6124001133200051
711115223212334
oct1513344353437
9354173886334
10113205434143
114401257523a
1219b34330027
13a8a161bcb9
14569cbc498b
152e2871accd
hex1a5b91d71f

113205434143 has 8 divisors (see below), whose sum is σ = 113282735040. Its totient is φ = 113128165920.

The previous prime is 113205434101. The next prime is 113205434159. The reversal of 113205434143 is 341434502311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113205434143 is a prime.

It is a super-2 number, since 2×1132054341432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113205432143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12049978 + ... + 12059368.

It is an arithmetic number, because the mean of its divisors is an integer number (14160341880).

Almost surely, 2113205434143 is an apocalyptic number.

113205434143 is a deficient number, since it is larger than the sum of its proper divisors (77300897).

113205434143 is an equidigital number, since it uses as much as digits as its factorization.

113205434143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16337.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 113205434143 its reverse (341434502311), we get a palindrome (454639936454).

The spelling of 113205434143 in words is "one hundred thirteen billion, two hundred five million, four hundred thirty-four thousand, one hundred forty-three".

Divisors: 1 3389 3557 9391 12054673 31826099 33403787 113205434143