11321000115 has 16 divisors (see below), whose sum is σ = 18154499328. Its totient is φ = 6024233696.

The previous prime is 11321000113. The next prime is 11321000123. The reversal of 11321000115 is 51100012311.

It is a cyclic number.

It is not a de Polignac number, because 11321000115 - 2¹ = 11321000113 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 11321000094 and 11321000103.

It is not an unprimeable number, because it can be changed into a prime (11321000113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 845199 + ... + 858488.

It is an arithmetic number, because the mean of its divisors is an integer number (1134656208).

Almost surely, 2^11321000115 is an apocalyptic number.

11321000115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11321000115 is a deficient number, since it is larger than the sum of its proper divisors (6833499213).

11321000115 is a wasteful number, since it uses less digits than its factorization.

11321000115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1704138.

The product of its (nonzero) digits is 30, while the sum is 15.

Adding to 11321000115 its reverse (51100012311), we get a palindrome (62421012426).

The spelling of 11321000115 in words is "eleven billion, three hundred twenty-one million, one hundred fifteen", and thus it is an aban number.