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11321014213 = 41927019127
BaseRepresentation
bin10101000101100100…
…01111011111000101
31002012222111002221201
422202302033133011
5141141134423323
65111212342501
7550355014225
oct124262173705
932188432851
1011321014213
11488a4655a3
12223b474a31
1310b55a23a2
14795794085
15463d4e8ad
hex2a2c8f7c5

11321014213 has 4 divisors (see below), whose sum is σ = 11348033760. Its totient is φ = 11293994668.

The previous prime is 11321014151. The next prime is 11321014241. The reversal of 11321014213 is 31241012311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11321014213 - 221 = 11318917061 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11321014273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13509145 + ... + 13509982.

It is an arithmetic number, because the mean of its divisors is an integer number (2837008440).

Almost surely, 211321014213 is an apocalyptic number.

It is an amenable number.

11321014213 is a deficient number, since it is larger than the sum of its proper divisors (27019547).

11321014213 is an equidigital number, since it uses as much as digits as its factorization.

11321014213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27019546.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11321014213 its reverse (31241012311), we get a palindrome (42562026524).

The spelling of 11321014213 in words is "eleven billion, three hundred twenty-one million, fourteen thousand, two hundred thirteen".

Divisors: 1 419 27019127 11321014213