Base | Representation |
---|---|
bin | 110100101110000010… |
… | …1100001011100000011 |
3 | 101211020002022020102011 |
4 | 1221130011201130003 |
5 | 3323330302220001 |
6 | 124002043033351 |
7 | 11115356661016 |
oct | 1513405413403 |
9 | 354202266364 |
10 | 113214101251 |
11 | 44017454a39 |
12 | 19b3720b857 |
13 | a8a3364c74 |
14 | 569dddd37d |
15 | 2e2937dd51 |
hex | 1a5c161703 |
113214101251 has 4 divisors (see below), whose sum is σ = 114381257032. Its totient is φ = 112046945472.
The previous prime is 113214101207. The next prime is 113214101257. The reversal of 113214101251 is 152101412311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 152101412311 = 67 ⋅2270170333.
It is a cyclic number.
It is not a de Polignac number, because 113214101251 - 27 = 113214101123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113214101257) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 583577745 + ... + 583577938.
It is an arithmetic number, because the mean of its divisors is an integer number (28595314258).
Almost surely, 2113214101251 is an apocalyptic number.
113214101251 is a deficient number, since it is larger than the sum of its proper divisors (1167155781).
113214101251 is an equidigital number, since it uses as much as digits as its factorization.
113214101251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1167155780.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 113214101251 its reverse (152101412311), we get a palindrome (265315513562).
The spelling of 113214101251 in words is "one hundred thirteen billion, two hundred fourteen million, one hundred one thousand, two hundred fifty-one".
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