Base | Representation |
---|---|
bin | 1010010010111111111111… |
… | …1001111011100100010011 |
3 | 1111002022212001012212021011 |
4 | 2210233333321323210103 |
5 | 2440442444220414420 |
6 | 40025012354311351 |
7 | 2245645056614614 |
oct | 244577771734423 |
9 | 44068761185234 |
10 | 11321532201235 |
11 | 3675486859743 |
12 | 132a232288557 |
13 | 6418011b5729 |
14 | 2b1d72285c0b |
15 | 14977438e95a |
hex | a4bffe7b913 |
11321532201235 has 4 divisors (see below), whose sum is σ = 13585838641488. Its totient is φ = 9057225760984.
The previous prime is 11321532201173. The next prime is 11321532201241. The reversal of 11321532201235 is 53210223512311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11321532201235 - 27 = 11321532201107 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11321532201197 and 11321532201206.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1132153220119 + ... + 1132153220128.
It is an arithmetic number, because the mean of its divisors is an integer number (3396459660372).
Almost surely, 211321532201235 is an apocalyptic number.
11321532201235 is a deficient number, since it is larger than the sum of its proper divisors (2264306440253).
11321532201235 is an equidigital number, since it uses as much as digits as its factorization.
11321532201235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2264306440252.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 11321532201235 its reverse (53210223512311), we get a palindrome (64531755713546).
The spelling of 11321532201235 in words is "eleven trillion, three hundred twenty-one billion, five hundred thirty-two million, two hundred one thousand, two hundred thirty-five".
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