113220434131 has 16 divisors (see below), whose sum is σ = 131873575680. Its totient is φ = 95194133280.

The previous prime is 113220434039. The next prime is 113220434137. The reversal of 113220434131 is 131434022311.

It is a cyclic number.

It is not a de Polignac number, because 113220434131 - 2⁷ = 113220434003 is a prime.

It is a super-2 number, since 2×113220434131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113220434096 and 113220434105.

It is not an unprimeable number, because it can be changed into a prime (113220434137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 106941 + ... + 487726.

It is an arithmetic number, because the mean of its divisors is an integer number (8242098480).

Almost surely, 2^113220434131 is an apocalyptic number.

113220434131 is a deficient number, since it is larger than the sum of its proper divisors (18653141549).

113220434131 is an equidigital number, since it uses as much as digits as its factorization.

113220434131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 595194.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 113220434131 its reverse (131434022311), we get a palindrome (244654456442).

The spelling of 113220434131 in words is "one hundred thirteen billion, two hundred twenty million, four hundred thirty-four thousand, one hundred thirty-one".