Base | Representation |
---|---|
bin | 110100101110010000… |
… | …0110001010010001001 |
3 | 101211020120202010110221 |
4 | 1221130200301102021 |
5 | 3323334114302131 |
6 | 124002500110041 |
7 | 11115504460333 |
oct | 1513440612211 |
9 | 354216663427 |
10 | 113221244041 |
11 | 44020493474 |
12 | 19b39695321 |
13 | a8a4996179 |
14 | 56a0d3c453 |
15 | 2e29ce0411 |
hex | 1a5c831489 |
113221244041 has 8 divisors (see below), whose sum is σ = 119849273280. Its totient is φ = 106774804752.
The previous prime is 113221244027. The next prime is 113221244057. The reversal of 113221244041 is 140442122311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113221244041 - 211 = 113221241993 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113221243997 and 113221244015.
It is not an unprimeable number, because it can be changed into a prime (113221224041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45396205 + ... + 45398698.
It is an arithmetic number, because the mean of its divisors is an integer number (14981159160).
Almost surely, 2113221244041 is an apocalyptic number.
It is an amenable number.
113221244041 is a deficient number, since it is larger than the sum of its proper divisors (6628029239).
113221244041 is an equidigital number, since it uses as much as digits as its factorization.
113221244041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90794975.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 113221244041 its reverse (140442122311), we get a palindrome (253663366352).
The spelling of 113221244041 in words is "one hundred thirteen billion, two hundred twenty-one million, two hundred forty-four thousand, forty-one".
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